How about, as recently pointed out by @anntzer on github:

```python

fig, axs = plt.subplots(1, 2, figsize=[14, 4])

plt.setp(axs, ‘xlabel’, labels[0], ‘ylabel’, labels[1])

```

or, suppose you don’t want to repeat labels except on outer

```python

fig, axs = plt.subplots(3, 3, figsize=[14, 4])

plt.setp(axs[-1,:], ‘xlabel’, labels[0])

plt.setp(axs[0,:], ‘ylabel’, labels[1])

```

Cheers, Jody

> On 27 Oct 2017, at 4:17 AM, Andrei Berceanu <

[hidden email]> wrote:

>

> Hi all,

>

> Please consider this code:

>

> fig, (ax1, ax2) = plt.subplots(ncols=2, figsize=[14,4])

>

> for ax in (ax1, ax2):

> ax.set_xlabel(labels[0])

> ax.set_ylabel(labels[1])

>

> This could be simplified if I could just loop though the x and y axes of each subplot, something like:

>

> for index, ax in enumerate((ax1, ax2)):

> ax.set_label[index](labels[index])

>

> Is there some way of achieving this in Matplotlib? From what I found, it seems one can only refer to the axes using x and y, and so I don't know how to loop over both of them.

>

> Thank you,

> Andrei

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Jody Klymak

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